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By Noel M. Morris (auth.)

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D. 13), then we say that R 1 3 = 0. In order to determine the mutual resistance associated with two loops, replace each genenttor in the mutual branch by their internal resistances and open-circuit all other branches. Calculate the resistance of the mutual branch. 27. 23. 23 Solution The self-resistance of loop 1 in which I 1 circulates is (R 1 + R 2 + R 3 ), and the resistance in the mutual branch between meshes 1 and 2 is R 2 , hence R 11 =R 1 +R 2 +R 3 and R 12 =-R 2 . Since no branch exists that is common to both mesh l and mesh 3, then R 13 = 0.

D. in loop l due to the flow of current I 3 in loop 3. d. 13), then we say that R 1 3 = 0. In order to determine the mutual resistance associated with two loops, replace each genenttor in the mutual branch by their internal resistances and open-circuit all other branches. Calculate the resistance of the mutual branch. 27. 23. 23 Solution The self-resistance of loop 1 in which I 1 circulates is (R 1 + R 2 + R 3 ), and the resistance in the mutual branch between meshes 1 and 2 is R 2 , hence R 11 =R 1 +R 2 +R 3 and R 12 =-R 2 .

15 for current sharing in parallel circuits. 10b, then the parameters of the two circuits are related to one another. 8 must also be equivalent in every respect. 5. 5 V, and for R of 5 n. 2 S. 5. f. f. being replaced meanwhile by their respective internal resistances. This principle is not confined to electrical circuits, and may be applied to many forms of physical and mechanical systems. 6. 1la using the superposition principle. f. taken separately is calculated, the net circuit current being the sum of the two currents.

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