By Schaaf W.L.
Cultivated by way of the traditional Greeks greater than thousand years in the past, geometry is without doubt one of the oldest highbrow targets of guy. Its origins may be traced again even farther to the Babylonians and Egyptians. In essence, Egyptian geometry was once an easy, empirical artwork of sensible dimension, fostered via the need of widespread land-surveying as a result of inundations by way of the river Nile, and likewise through the astronomical interest and spiritual culture of the Egyptians. Their geometry used to be, in brief, a rule-of-thumb geometry.
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X\O Qo UFY . The above reasoning shows t h a t t h e f i r s t category r e l a t i v e t o X\A* . A \ A* i s of But a s e t which i s o f t h e f i r s t category r e l a t i v e t o an open s e t which c o n t a i n s i t i s obviously o f t h e f i r s t category r e l a t i v e t o t h e whole space. We remark t h a t a s e t only i f . i s o f t h e first category. Conversely assume an open set 0 such that C A O Then C* = 0" and hence shows that C * \ C C* that there exist is of the first category.
T h e n a countable i n t e r s e c t i o n o f hence M i s a l s o 6-compact is fi X 6-compact s u b s e t s i n , i s standard. Baire8s Hn/r F i f and o n l y i f . ,M union f of an open A is a as b e f o r e ) . This con- cludes the proof. We denote the coordinatewise ordering in $la by Let 5 . be an arbitrary set equipped with the partial order S . 5 S is (by our definition) an analytically ordered set p:iw-*S if there exist a mapping such that the follo- wing conditions are fulfilled i) n i m ==+ (4 p(n)< ii) For all s 6 S The order relation there exist < .
It is then clear that fa,Bn] is a 32 I H I OKLMS 01 SLPARATION. This concludes the p r o o f . The next theorem is vital for the isomorphism theorems. Then it is easy to see that there exist v and u such that .. By induction we can , f o r all p , THI OK1 M S 01 SLPARATION. LTC 3 cannot be separated by n sets,in particular and A1( (ml,. ,mp)) . A 33 A2( (mi,. Let f:Y -+X and . Now f-’(Si) i=1,2 belongs to S(c&),so: THEOREMS OF SEPARATION, ETC. As can now be used to show that g(Si)6S(g) (1,g)evidently is a sets C1,C2 space,we can find disjoint i=1,2.